Consider a 13-meter steel cantilever beam (a beam
attached to a wall that doesn't allow for any deflection on that side),
anchored on the right, has a downward load of 100 Newtons applied to it
7 meters from the left end. How far down will the left end of the beam
The first step is to determine the value of Young's Modulus to be used;
since the beam is made of steel, we go with the given steel value:
206,850 MPa, which is 206,850,000,000 Pa (remember, since everything
else is in metric and using N/m/s, we use single Pascals).
Next, determine the moment of inertia for the beam; this
usually is a value given in most textbook problems, or if it needs to
be calculated, a listing of formulas for determining moment of inertias
for many common geometries is provided here. *Note: this application uses the Area Moments of Inertia, which are listed first.
For this example, we're just going to say that the beam is square and has a crossection side length of 0.5m. So...
This is a good time to choose the loading case, so looking over the
list, it looks like loading case #13 is our best bet; its beam is
cantilevered on one end, and it has the single point load that is not a
set distance from either end.
After checking the load-case button, enter in the rest of the values as
they are given: a point load equal to 100 Newtons, total beam length is
13 meters, no applied moments or distributed loads, partial length "a"
is 7 meteres, partial length "b" is the remaining 6 meters, and voila!
ready to see just how far this beam gets bent. Click on the "Submit For
Calculation" button to see the results.